Part A A car of mass M = 1100 traveling at 50.0 km/hr enters a banked turn cover

Question

Part A A car of mass M = 1100 traveling at 50.0 km/hr enters a banked turn covered with ice. The road is banked at an angle ?, and there is no friction between the road and the car's tires. (Figure 1) . Use g= 9.80 m/s2 throughout this problem. What is the radius r of the turn if ? = 20.0(assuming the car continues in uniform circular motion around the turn)? express the answer in meters Part B Now, suppose that the curve is level (? =0) and that the ice has melted, so that there is a coefficient of static friction between the road and the car's tires.(Figure 2) What is the minimum value of the coefficient of static friction between the tires and the road required to prevent the car from slipping? Assume that the car's speed is still 50.0 km/hr and that the radius of the curve is given by the value you found for r in Part A. can you work it out because i dont understand Physics

Explanation / Answer

(a)

the radius r of the turn if = 20.0

according FBD

for not slipping mgsin = mv2cos/r

= 20, v = 50 km/hr = 13.89 m/s

=> r = v2cot/g = 54 m.

(b)

mgsin + mgcos mv2cos/r

given that = 0, r = 54 m(from part A), v = 50 km/hr = 13.89 m/s

=> v2/gr

=> 0.364

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