7.) What is the energy stored in the 10.1 F capacitor of a heart defibrillator c

Question

7.) What is the energy stored in the 10.1 F capacitor of a heart defibrillator charged to 10.3 kV?

8.) A doubly charged ion is accelerated to an energy of 22 keV by the electric field between two parallel conducting plates separated by 9 cm. What is the electric field strength between the plates? Give answer in terms of 105 V/m.

9.) An electrostatic paint sprayer has a potential of 25.0 kV that repels paint droplets onto a grounded object. What charge must a 0.93 mg drop of paint have to arrive at the object with a speed of 9 m/s? Give answer in terms of 10-10 C.

Explanation / Answer

(7) ans

Given that

capacitance C=10.1*10^-6 F

potential difference V=10.3kv

basing on the concept b/w electric potential and capacitance

now we find the energy stored in the capacitor

the energy stored in capacitor E=1/2cv^2

=1/2*10.1*10^-6*(10.3*1030^2

=535.7545 J

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(8) ans

Given that

eergy E=22KeV=22*1.6*10^-16=35.2*10^-16 J

charge q=3.2*10^-19 C

distance b/w plates d=9 *10^-2 m

basing on the concept of electric potential and capacitance

now we find the electric field strength b/w the plates

energy E=qdE

35.2*10^-16=3.2*10^-19*9*10^-2*E

electric field E=1.235087719*10^5 V/m

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(9) ans

Given that

electric potential V=25 kv

speed v=9 m/s

mass m=0.93*10^-6 kg

basing on the concpt of electric potential

now we find the charge

1/2mv^2=qv

1/2*0.93*10^-6*9^2=Q*25*10^3

charge Q=15.066*10^-10 c

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