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7. suppose a rod move to the right, so that the area enclosed by the conducting

ID: 1480831 • Letter: 7

Question


7. suppose a rod move to the right, so that the area enclosed by the conducting path increases at rate of 2.0 * 10^2 m/s . find the magnitude and direction of the current of the resistance of the conducting path is 3 ohms and the magnetic field is 0.9 T.

8. two long straight parallel wires 8.00 centimeters apart ( both of them 10 m long as shown). they are carrying the same current of 6.0 A, and opposite directions. find the magnetic field at the middle point between these two wires.

9. a magnetic field of magnitude 0.40 T is directed vertically upward. find the magnetic flux through a flat surface of area 20 cm^2, if the surface is at an angle of 60 degrees with the vertical.

10. suppose a rod moves to the left with a velocity of 10.00 cm/s, and the length of it is 30.00 cm. find the magnitude and direction of the current of the resistance of the past is 0.6 ohms and the magnetic field is a 0.9 T.


lmoves to right, so that the area enclosed by the conducting path increas s. find the magnitude and direction of the current of the resistance of the and the magnetic field is of 0.9T ght parallel wires 8.00 cm apart (both of them 10 m long) as shown. They ent of 6.0A, and opposite directions. Find the magnetic field at the middle wwwl

Explanation / Answer

7.

dA / dt = rate of increase of area = 200

B = magnetic field = 0.9 T

R = resistance = 3 ohms

induced EMF is given as

E = B (dA / dt ) = 0.9 x 200 = 180 volts

induced current is given as

i = E/R = 180 / 3 = 60 A

direction of current Using right hand rule comes out to be in clockwise direction

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