A 425-g block is dropped onto a vertical spring with spring constant k =110.0 N/

Question

A 425-g block is dropped onto a vertical spring with spring constant k =110.0 N/m. The block becomes attached to the spring, and the spring compresses 55.4 cm before momentarily stopping. While the spring is being compressed, what work is done on the block by its weight? 2.31 J While the spring is being compressed, what work is done on the block by the spring force? -1.69 times 10^1 J. What is the speed of the block just before it hits the spring? (Assume that friction is negligible.) 8.28 m/s If the speed at impact is doubled, what is the maximum compression of the spring? 1/2 k x^2 = mgx + 1/2 m v^2

Explanation / Answer

Apply conservation of energy

0-1/2 m v'^2 + mgd'- 1/2 k d^2

d' = mg + sqrt m^2 g^2 + mk v'^2/k

=0.425(9.8) + sqrt( 0.425)^2 ( 9.8)^2 + (0.425) ( 110) ( 16.56)^2/110

=1.06 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.