A 41.0-cm wire is moving to the right at a speed of 6.90 m/s across two parallel

Question

A 41.0-cm wire is moving to the right at a speed of 6.90 m/s across two parallel wire rails that are connected on the left side, as shown in the figure. The whole apparatus is immersed in a uniform magnetic field which has a magnitude of 0.810 T and is directed into the screen.

What is the emf induced in the wire?

A 410-cm wire is moving to the right at a speed of 6.90 m/s across two parallel wire rails that are connected on the left side, as shown in the figure. The whole apparatus is immersed in a uniform magnetic field which has a magnitude of 0.810 T and is directed into the screen × 0.810 T What is the emf induced in the wire? 6.90 m/s 41.0 cm Number 2.29 The induced emf causes a current to flow in the circuit formed by the moving wire and the rails. In what direction does the current flow around the circuit ? O counter-clockwise O clockwise

Explanation / Answer

Induced emf = B*l*v
e = 0.810 * 0.41 * 6.90 V
e = 2.29 V


As the Loop is moving towards Right, Flux through the area is increasing in Downward direction. Current will be induced in such a way so as to counter this effect.

Direction of current - Counter-Clockwise.

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