A 400 gram block, attached to the end of an ideal srping(horizontally) with the
ID: 1728607 • Letter: A
Question
A 400 gram block, attached to the end of an ideal srping(horizontally) with the force constant k=10N/m, undergoes simpleharmonic motion with a maximum displacement of 0.05 m from therelaxed position. Ignore any friction or air resistance 1. Compute the aplitude of Oscillations______________ 2. Maximum speed of block __________________ 3. Magnitude of the maximum acceleration ofblock_______________ 4. Angular frequency of Oscillation_____________________ Pleas show work or and final answer. I have quite a fewmore questions on this problem so this would assist in answeringthe rest. A 400 gram block, attached to the end of an ideal srping(horizontally) with the force constant k=10N/m, undergoes simpleharmonic motion with a maximum displacement of 0.05 m from therelaxed position. Ignore any friction or air resistance 1. Compute the aplitude of Oscillations______________ 2. Maximum speed of block __________________ 3. Magnitude of the maximum acceleration ofblock_______________ 4. Angular frequency of Oscillation_____________________ Pleas show work or and final answer. I have quite a fewmore questions on this problem so this would assist in answeringthe rest.Explanation / Answer
given that mass of block = m = 400g = 0.4kg k = 10N/m maxium dipalacement = xmax = 0.05m maxdiplacement gives amplitude = A = 0.05m maximum speed of block vmax = k/m * A =10/0.4 * 0.05 = 0.25m/s Magnitude of the maximum acceleration of block amax = k/m * A = 10/0.4 * 0.05 =1.25m/s2 angular frequwncy = = k/m = 10/0.4= 5 rad/s angular frequwncy = = k/m = 10/0.4= 5 rad/sRelated Questions
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