In an experiment one of the forces exerted on a proton is F = -alpha x^2 i, wher

Question

In an experiment one of the forces exerted on a proton is F = -alpha x^2 i, where alpha = 12 N/m^2. Part B How much work does F do when the proton moves along the straight-line path from the point (0.10 m, 0) to the point (0.30 m, 0)? Part B How much work does F do when the proton moves along the straight-line path from the point (0, 30 m, 0) to the point (0.10 m, 0)? Part D Is the force F conservative? Explain. If F is conservative, what is the potential energy function for it? Let U = 0 when x = 0.

Explanation / Answer

part D)

as F = - alpha * x^2 i

F = -12 * x^2 * i

U = integration(- F . dx) from 0 to x

U = 12 * x^3/3

U = 4 * x^3

the potential energy is 4 * x^3

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