1.Consider the Resonance In an Air Column Experiment. You find maxima in sound i

Question

1.Consider the Resonance In an Air Column Experiment. You find maxima in sound intensity at locations 13.8 cm, 49.1 cm, and 83.9 cm on your tube for a 490 Hz tuning fork. Find the speed of sound to the nearest tenth of a m/s. Enter a numerical value without units. Do not write in scientific notation.

2.Consider the Resonance In an Air Column Experiment. You find maxima in sound intensity at locations 13.8 cm, 49.1 cm, and 83.9 cm on your tube for a 490 Hz tuning fork. Find the temperature in the room to the nearest tenth of a oC. Enter a numerical value without units. Do not write in scientific notation.

3.Consider the Resonance In an Air Column Experiment. You find maxima in sound intensity at locations 13.8 cm, 49.1 cm, and 83.9 cm on your tube for a 490 Hz tuning fork. What is the smallest frequency sound that you would be able to find a resonance pattern for by measuring with a 1.00 m long sliding tube (you can measure a difference in position of up to 1 meter), assuming ideal conditions exist. Enter a numerical value, TO THE NEAREST TENTH of a Hz. Do not enter units. Do not write in scientific notation.

Explanation / Answer

Q1.

difference between successive maximum intensity is equal to wavelength/2

so from first two locations, wavelength/2=49.1-13.8 =35.3 cm

from last two locations, weavelength/2=83.9-49.1=34.8 cm

taking average, wavelength/2=(35.3+34.8)/2=35.05

==>wavelength=70.1 cm=0.701 m

frequency=490 Hz

as speed of sound=frequency*wavelength

==>speed of sound=490*0.701=343.49 m/s

in nearest tenth of m/s ,speed of sound observed=343.5 m/s

Q2.

speed of sound in air is given by

331.4+0.6*T

where T is temperature in celcius

so 343.5=331.4+0.6*T

==>T=20.167 degree celcius

to the nearest tenth of degree celcius, temperature=20.2 degree celcius

Q3.

speed=wavelength*frequency

frequency will be lowest if wavelength is highest

we know resonance occurs, if length=wavelength/4, 3*wavelength/4 etc.

so for maximum wavelength, length=wavelength/4

given length=1 m

==>wavelength=4 m

then frequency=speed/wavelength=343.5/4

=85.875 Hz

so smallest frequency of sound that can be heard is 85.875 Hz

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