Use the worked example above to help you solve this problem. An airplane travels

Question

Use the worked example above to help you solve this problem. An airplane travels 3.95 times 10^2 km due east and then travels an unknown distance due north. Finally, it returns to its starting point by traveling a distance of 519 km. How far did the airplane travel in the northerly direction? 336 km A plane flies 337 km due south, then turns and flies 622 km at a heading north of east, until it's due east of its starting point. If the plane now turns and heads for home, how far will it have to go? _______ up with an answer smaller than the second leg of the trip. Use a drawing to sort out the given information and help you to determine the desired unknown. km

Explanation / Answer

Here ,

for the plane , for it's final displacement

-337 j + 622 * (cos(theta) i + j * sin(theta)) = 0

for north south displacement to be zero

622 * sin(theta) - 337 = 0

theta= 32.8 degree

Now, distance travelled to go home = 622 * cos(32.8 degree)

distance travelled to go home = 522.8 km

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