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CAT 19% Sun 5:25 AM E Chrome File Edit View History Bookmarks People Window Help MasteringPhysics: Ch 36 HW Secure https session.masteringphysics.com 73205733 Spring 2017 PHY 232 ELI Signed in as kalid kel Ch 36 Hw Exercise 36.18 Resources previous l 10 of 13 I ne Exercise 36.18 Part A Parallel rays of monochromatic light with wavelength 585 lf the intensity at the center of the central maximum is 3.20x10-4 W/m what is the intensity at a point on the screen that is 0.760 mm from nm illuminate two identical slits and produce an the center of the central maximum? interference pattern on a screen that is 75.0 cm from the slits. The centers of the slits are 0.640 mm apart and the Express your answer to three significant figures and include the appropriate units. width of each slit is 0.434 mm. I- 5.5 10 mm Submit My Answers Give Up incorrect; Try Again; 7 attempts remaining Continue Provide Feedback Course Materials 30

Explanation / Answer

we know that:

tan A = y/R

tan A = 0.760*10^-3/(75*10^-2) = 1.013*10^-3 rad

Since angle is small, So

tan A = A = sin A

So, Now

phi = 2*pi*d*sin A/lambda

phi = 2*pi*0.64*10^-3*sin (1.013*10^-3 rad)/(585*10^-9) = 6.9632 rad

beta = 2*pi*a*sin A/lambda

beta = 2*pi*0.434*10^-3*sin (1.013*10^-3 rad)/(585*10^-9) = 4.722 rad

Now Intensity is given by:

I = I0*(cos phi/2)^2*((sin (beta/2))/(beta/2))^2

I = 3.2*10^-4*(cos 6.9632/2)^2*((sin 2.361)/2.361)^2

I = 2.53*10^-5 W/m^2

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