A. a coil of wire of diameter .35m and 85 turns has a current of 3 mA running th

Question

A. a coil of wire of diameter .35m and 85 turns has a current of 3 mA running through it. what is the strength of the magnetic field at the center of the coil
B. The primary coil of a transformer has 30 turns and the secondary coil has 120 turns. If the input voltage of the transformer is 20 v what is the output voltage?


A. a coil of wire of diameter .35m and 85 turns has a current of 3 mA running through it. what is the strength of the magnetic field at the center of the coil
B. The primary coil of a transformer has 30 turns and the secondary coil has 120 turns. If the input voltage of the transformer is 20 v what is the output voltage?



B. The primary coil of a transformer has 30 turns and the secondary coil has 120 turns. If the input voltage of the transformer is 20 v what is the output voltage?

Explanation / Answer

(A) B = u0 I N / (2 R)

= (4pi x 10^-7 x 3 x 10^-3 x 85) / (2 x (0.35/2))

= 9.16 x 10^-7 T

(B) Np = 30

Ns = 120 turns

Vp = 20 Volt

Ns / Np = Vs / Vp

120 / 30 =Vs / 20

Vs = 80 Volt

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