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webassign netweb/Student/Assignment-Responses submithdepa15032112 vated Getting suarted Suggested stes Web Sice Gallery Ask Your Te My Notes -as points SerPSE9 31 P048 A motor in normal operation carries a direct current of o 420 A when connected to a 120 v power supply. The resistance in the motor windings is 10.4 n. Determine the following values. (a) While in normal operation, what is the back emf generated by the motor? (b) While in normal operation, at what rate is internal energy produced in the windings? (c) What if? Suppose that a malfunction stops the motor shaft from rotating. At what rate will internal energy be produced in the windings in this case? (Most motors have a thermal switch that will turn off the motor to prevent overheating when this occurs.) Need Help? Read My Notes o Ask your Teacher 31 P041 A long solenoid with 1.35 x 103 turns per meter and radius 2.00 cm carries an oscillating current I 3.00 sin 90nt, where I is in amperes and t is in seconds (a) what is the electric field induced at a radius r 1.00 cm from the axis of the solenoid? (use the following as necessary: t. Let E be Firefow automatically sends some data to MoBla lo that we can improve your optnence. Onose What Share

Explanation / Answer

Here ,

I = 0.420 A

V = 120 V

a)

R = 10.4 Ohm

back emf = V - I * R

back emf = 120 - 0.420 * 10.40

back emf = 115.6 V

b)

thermal energy produced in windings = 0.420^2 * 10.40

thermal energy produced in windings = 1.83 W

c) for no rotation

thermal energy produced in windings = V^2/R

thermal energy produced in windings = 120^2/10.40

thermal energy produced in windings = 1384 W

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