we want to make 1L tris uct aitmouht of water RUCt ai vblume Problems: 1) We wan

Question

we want to make 1L tris uct aitmouht of water RUCt ai vblume Problems: 1) We want to make 1L of 1M Tris-base pH 7.3 buffer (MW of Tris-base is 121.14; Tris-base dissolved in solution is basic.) How much Tris-base powder is used? Might HCI or NaOH be used to pH the Tris solution? How much water is added? 2) We have the below stock solutions- we want to make 500ml of a 50mM Tris/ 1mM EDTA solution: 1M Tris pH 7.3 0.5M EDTA pH 8.0 How much of the Tris stock solution would you add? How much of the EDTA stock solution would you add? How much water would be added?

Explanation / Answer

1. The answer is

Molarity = Weight/Gram molecular weight * Volume in liters.

So, Weight = Molarity X Gram molecular weight X Volume in liters.

Here,
Molarity = 1
Gram molecular weight = 121.14
Volume in liters = 1.

So, the weight = 1 * 121.14 * 1 = 121.14 grams.

To prepare 1M Tris base, you are required 121.14 grams of Tris base.

As the tris base is alkali, to achieve the pH 7.3 HCl to be used. As the base is strong, it would be better if we use concentrated HCl instead of 1N Hcl.

To prepare the solution, first dissolove the 121.14 grams of Tris base in 500 ml of water and adjust the final volume to 1 litre with double distilled water.

ACCORDING TO CHEGG GUIDELINES WE HAVE TO ANSWER ONE QUESTION AT A TIME. POST THE REST AS SPERATE QUESTIONS, THEN I CAN HELP YOU.

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