The drawing shows a collision between two pucks on an air-hockey table. Puck A h

Question

The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0200 kg and is moving along the x axis with a velocity of +5.88 m/s. It makes a collision with puck B, which has a mass of 0.0400 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

https://edugen.wileyplus.com/edugen/courses/crs7924/art/qb/qu/c07/EAT_1322915795822_0_1136023348045595.gif

Explanation / Answer

Ma 0.02 kg and 5.88 m/s , 65 deg +Y
Mb 0.04 kg and 0.0 m/s , 37 deg -Y

MaVi = ma cos 65 Va + mb cos 37 Vb
0.1176 =0.008452Va + 0.031944Vb …………………eq1

MbVi = ma sin 65 Va - mb sin 37 Vb
0 = 0.018126Va - 0.024072Vb
0.018126Va = 0.024072Vb

Va = 0.024072Vb / 0.018126

Va = 1.32803707 Vb……………………………..substitute in eq1

0.1176 =0.008452*(1.32803707 Vb) + 0.031944Vb

0.1176 = 0.04316857 Vb

Vb = 2.724 m/second

Va = 1.32803707 x 2.724

Va = 3.617 m/second

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