WileyPLUS C Secure https:// wileyplus.com/edugen/student/mainfr.uni edugen Apps
ID: 1596743 • Letter: W
Question
WileyPLUS C Secure https:// wileyplus.com/edugen/student/mainfr.uni edugen Apps O Formatting IThe Java Complete printf for Je Fs used 2007 Lexus Es 3 D New Tab cts used 2009 Toyota Ava Articles citations with KAu Get Your Homework Icts used 2007 Toyota Ava WileyPLUS Halliday, Fundamentals of Physics, 10e Physics (PHYS 1303, 1304, 1307, 1308 Home Read, Study & Practice Aaaanment Open Assignment FULL SCREEN PRENTERVERSION BACK NEXT Chapt 25, P 022 HW5 In the figure V 13 V CL 10 uF, and C2 Ca- 17 HF. Switch s is first thrown to the left side until capacitor 1 reaches equilibrium. Then the switch is thrown to the right. When equilibrium is again reached, how much charge is on capacitor Number the absolute tolerance is +/-1.0E-7 Click if you would like to show work for this question: open show Vork Chapter 25. Problem 014 Question Attempts: o of 5 used SAVE LAER SUBMITANswER copyright o 2000-2017 by John Wiley& Sons, Inc. or related companies. All rights reserved. Chapter 25 Problem License Agreement I Erbac Poicx 20DQ 2017 lohn Busans. Inc. All Rights Reserved. A Division of lohn Sans Inc. Version 4.22. 8:38 PM ENG Ask me anythingExplanation / Answer
V= 13 V
C1 = 10 uF
C2= C3 = 17 uF
initially charge on C1 ( when switch is thrown left side) = c1*V = 10*13 = 130 uC
this charge will distributes, so.potential drop in the circuit will be ,V' = 130 *10-6 / total capacitance
since C1 and C2,C3 are in parallel so total capacitance = C1+ C2+C3 = 10+ 17 +17 = 44 uF
so V' = 130*10-6 / 44*10-6 = 2.95 volt
Since capacitance in parallel so potential drop across them= 2.95 volt
charge on c1 , Q1 = C1* V' = 10*2.95 = 29.5 uC
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.