Wiley PLUS Cutnell, Physics, 10e Help I System Announcements NEXT PRINTER VERSIO

Question

Wiley PLUS Cutnell, Physics, 10e Help I System Announcements NEXT PRINTER VERSION SIGNMENT RESOURCES Chapter 05, Problem 52 W A a Chapter os Problem 55 Concept Simulation 5.1 reviews the concepts that are involved in this hagceros Problem 10 problem. A child is twirling a o.0244-kg ball on a string in a horizontal circle whose radius is o.134 m. The ball travels once around the circle in Chapter 09 Problem 15 0.367 s. (a) Determine the centripetal force acting on the ball. (b) If the speed is doubled, by what factor does the centripetal increase? chaoters Proteem Focus on Concepts Question Chapter 09, Problem 12 Review Score Review Results by Study objective (a) Number unts Units (b) Number Click if you would like to show work for this question: open show work u will learn while you earn points

Explanation / Answer

v = 2*pi*r/t = 2*pi*0.134/0.367 = 2.3 m/s

(a)

F = m*v^2/r = 0.0244*2.3^2/0.134 = 0.96 N

(b)

v1 = 2*v

F1 = m*v1^2/r = 4*m*v^2/r = 4*F

F1/F = 4

force increases by a factor of 4     <<-------answer

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net torque = 0

F*0.34 = M*0.054

190*0.34 = M*0.054

M = 1196.3 N     <<-------answer

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Q 69

torque = W*L*sintheta

torque = 49*0.55*sin30 = 13.475 Nm       <<-------answer

====================

(b)

torque = 18 Nm

18 = 49*0.55*sintheta

theta = 41.9 degrees    <<-------answer

====================

Q 09)

net torque about the fore fingers is zero

T*0.06 = 0.185*0.4/2 + (1.08*0.24) + (0.214*0.38)

T = 6.292 N      <<-------answer

(b)

along vertical Fnet = 0

F - T - (0.185+1.08+0.214)*g = 0

F - 6.292 - (0.185+1.08+0.214)*9.8 = 0

F = 20.8 N    <<-------answer

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