A 49 g piece of ice at 0.0 degree C is placed in an insulated calorimeter of neg

Question

A 49 g piece of ice at 0.0 degree C is placed in an insulated calorimeter of negligible heat capacity containing 100 g of water at 100 degree C. what is the final temperature of the water once thermal equilibrium is established? 40.8 * C You currently have 3 submissions for this question. Only 10 submission are allowed. You can make 7 more submissions for this question. Find the entropy change of the universe for this process. J/K You currently have 2 submissions for this question. Only 10 submission are allowed. You can make 8 more submissions for this question.

Explanation / Answer

mice = 49 g at 0 C
mwater = 100 g at 100 C
Final Temperature, Tf = 40.8 C

(b)
Entropy change of the universe = S_ice + S_water

S_ice = (Mi*Lf)/T_avg + (Mi*Cw*T)/T_avg
S_ice = (49 * 333.55) / 273 + (49*4.186*(40.8 - 0))/((313.8 + 273)/2)
S_ice = 88.4 J/k

S_water = (Mw*Cw*T)/T_avg
S_water = (100 * 4.186 * (40.8 - 100)) / ((313.8 + 373)/2)
S_water = -72.16 J/k

Entropy change of the universe = 88.4 - 72.16 J/k
Entropy change of the universe = 16.24 J/k

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