For the rest of this problem, use these numbers. Particle 1 has a charge of +50.

Question

For the rest of this problem, use these numbers. Particle 1 has a charge of +50.0 microcoulombs, and a mass of 3.60 milligrams. Particle 1 also has a speed, when it enters region A, of 5.00 m/s. For convenience, the diagram is repeated here. (d) If region A is a square measuring 90.0 cm on each side (the other regions have the same size as region A, of course), what is the magnitude of the magnetic field in region A? 1.2 T (e) From the instant particle 1 enters region A for the first time, until it leaves region B, how much time elapses? 0.524 s (f) If particle 2 has the same mass and the same speed as particle 1, what is the charge on particle 2? microcoulombs

Explanation / Answer

e) Here the particle 1 is completing 1.25 revolution

we know, time period of a particle, T = 2*pi*m/(B*q)

= 2*pi*3.6*10^-6/(1.2*50*10^-6)

= 0.377 s

so, time taken, t = 1.25*T

= 0.377*1.25

= 0.471 s

f) from the figure,

r2 = 4*r1

m2*v2/(B*q2) = 4*m1*v1/(B*q1)

1/q2 = 4/q1 (since m2 = m1 and q2 = q1)

==> q2 = q1/4

= 50/4

= 12.5 micro C

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