For the reaction, shown below, determine which statements are True and which are

Question

For the reaction, shown below, determine which statements are True and which are False.

3Fe(s) + Cr2O72-(aq) +14H+(aq) 3Fe2+(aq) + 2Cr3+(aq) + 7H2O(l)       o=1.77V

True False  The oxidation state of chromium in dichromate is +3.
True False  The oxidation state of hydrogen changes from +1 to 0.
True False  The reducing agent is Fe2+ (aq)
True False  The oxidizing agent is Fe2+ (aq)
True False  The chromium half-reaction takes place in a neutral solution.
True False  The highest oxidation state for oxygen in this reaction is 0.

Please help & explain.

I have already tried F, F, F, T, F, F, & F,F,T,F,F,F

Neither have worked yet...

Explanation / Answer

Solution :- For each statement correct answer is provided and explaination is provided.

The oxidation state of chromium in dichromate is +3. = False, because in dichromate oxidation state of chromium is +6

The oxidation state of hydrogen changes from +1 to 0. = False, because on both the sides oxidation state of hydrogen is +1

The reducing agent is Fe2+ (aq) =False, because Fe2+ is formed after oxidation of the Fe(s) therefore Fe(s) is reducing agent

The oxidizing agent is Fe2+ (aq) = False, because Cr^6+ is reduced to Cr^3+ that means oxidizing agent is Cr2O7^2-

The chromium half-reaction takes place in a neutral solution.= False, because reaction is taking place in acidic medium

The highest oxidation state for oxygen in this reaction is 0 =False, because at both sides of the equation oxidation state of the oxygen is -2 and not 0

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