Problem 31.65 Part C Determine the current through the R1 = 900 Express your ans

Question

Problem 31.65 Part C Determine the current through the R1 = 900 Express your answer with the appropriate units. Enter positive value if the current through the resistor is directed to the right and negative value if the current through the resistor is directed to the left. For the circuit in (Figure 1), assume the electric potential is zero at the negative terminal of the battery. Suppose that R1 = 900 . R2 = 1500 and E-30 V Submit My Answers Give Up Incorrect Iry Again, 6 attempts remaining Part D Determine the current through the resistor R2 = 1500 Express your answer with the appropriate units. Enter positive value if the current through the resistor is downward and negative value if the current through the resistor is upward 12-150 mA Submit My Answers Give Up Figure 1 Incorrect Iry Again, / attempts remaining Part E Determine the current through the 1200- resistor Express your answer with the appropriate units. Enter positive value if the current through the resistor is downward and negative value if the current through the resistor is upward 900 1200 300 Submit My Answers Give Up

Explanation / Answer

900 ohm and 300 ohm are series.

equivalent of these R' = 900 + 300 = 1200 ohm

now 1200 ohm and R' are in parallel connection.

Req = 1200 x 1200 / (1200 + 1200) = 600 ohm

now R1 annd 600 ohm are in series.

equivalent of these R" = R1 + 600 = 900 + 600 = 1500 ohm

this is on parallel connection with battery,

hence current through R" = V / R = 30 / 1500 = 0.02 A

D) potential difference across R2 is e.

current = e / R2 = 30 / 1500 = 0.02 A

E)this current will divide into 1200 ohm and (900 + 300) ohm branch.

both branch have same resistance.

hence current will divide.

current through 1200 ohm = 0.02/2 = 0.01 A

F) this current will divide into 1200 ohm and (900 + 300) ohm branch.

both branch have same resistance.

hence current will divide.

current through 900 ohm = 0.02/2 = 0.01 A

g) 900 ohm and 300 ohm resistor are in series.

so they will be having same current passing through them.

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