Problem 3.62 Part A The reaction between potassium superoxide, KO2, and CO2 AK02

Question

Problem 3.62 Part A The reaction between potassium superoxide, KO2, and CO2 AK02 +2CO22K2 CO3 +302 is used as a source of O2 and absorber of CO2 in self contained breathing equipment used by rescue workers. (Figure 1) How many moles of O2 are produced when 0.500 mol of KO2 reacts in this fashion? Express your answer with the appropriate units. HA no)Value Units Submit My Answers Give Up Part B How many grams of KO2 are needed to form 8.5 g of 02? Express your answer with the appropriate units. Submit My Answers Give Up Part C How many grams of CO2 are used when 8.5 g of O2 are produced? Express your answer with the appropriate units. mco)ValueUnits Submit My Answers Give Up Continue

Explanation / Answer

A)

from reaction,

moles of O2 produced = (3/4)*moles of KO2 reacted

= (3/4)*0.500 moles

= 0.375 moles

Answer: 0.375 moles

B)

Molar mass of O2 = 32 g/mol

mass of O2 = 8.5 g

molar mass of O2 = 32 g/mol

mol of O2 = (mass)/(molar mass)

= 8.5/32

= 0.2656 mol

According to balanced equation

mol of KO2 formed = (4/3)* moles of O2

= (4/3)*0.2656

= 0.3542 mol

mass of KO2 = number of mol * molar mass

= 0.3542*71.1

= 25.2 g

Answer: 25.2 g

C)

According to balanced equation

mol of CO2 required = (2/3)* moles of O2

= (2/3)*0.2656

= 0.1771 mol

mass of CO2 = number of mol * molar mass

= 0.1771*44.01

= 7.79 g

Answer: 7.79 g

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.