Please show calculations. Along, thin, rod of mass M 0.500kg and length L 1.00 m

Question

Please show calculations. Along, thin, rod of mass M 0.500kg and length L 1.00 m is free to pivot about a fixed pin located at U2. The rod is held in a vertical position as shown below. It is struck in an inleastic collision by a ball mass m 0.300 kg. The ball sticks to the end of the rod. If the ball was moving at an initial speed of vo 4m/s, then with what angular velocity (in radls) does the rod move the instant after the ball strikes it? The moment of inertia of a uniform rod rotating around its center of mass is ML fixed support m vo

Explanation / Answer

Lets use the law of conservation of momentum principle

m1v1 = (m1+m2)v

v = m1v1/(m1+m2)

v = 0.3*4/ (0.5+0.3)

v = 1.5 m/s

angular speed, w = v/r = 1.5/0.5 = 3 rad/s

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