I know the answer, I would just like a detailed explanation. A bicycle wheel is

Question

I know the answer, I would just like a detailed explanation.

A bicycle wheel is rotating on an axle through its center such that the magnitude of its angular momentum is L = 10 kg-m^2/s. Two constant forces begin acting on the wheel. One force has a magnitude of F_1 =30 N, is acting a distance of r_1 = 0.80 m from the center of the wheel, and is acting to rotate the wheel counter-clockwise. The other force has a magnitude of F_2 =120 N, is acting at r_2 =0.20 m from the center of the wheel, and is acting to rotate the wheel clockwise. Both of the forces F_1 and F_2 are perpendicular to the radius vector at the point of action. What is the magnitude of the angular momentum L of the wheel after the forces have been acting for A =10 seconds?

Explanation / Answer

Net torque = sum of torques because of all force

Torque = RXF

=> Net torque = 30*0.8 - 120*0.2 = 0

Since net torque on wheel is zero, angular momentum will not change with respect to time.

So L after 10 sec will be 10 kg m^2/s

=> b) Answer

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