I know that you use Cu2+/Cu as cathode, and ascorbic acid as anode. Therefore yo

Question

I know that you use Cu2+/Cu as cathode, and ascorbic acid as anode.

Therefore you have Ec-Ea=0.206 V
According to the table, redox potential of Cu2+/Cu is 0.340 V vs Standard hydrogen electrode
So you have 0.340 V - Ea=0.206 V
So Ea=0.134 V vs Standard hydrogen electrode
Standard hydrogen half cell has potential of 0 V. So the question is basically asking what is the potential of your anode.  I just don't know whether to use -.134 or +.134 (if the anode described is still the anode when compared to the hydrogen half cell.

Explanation / Answer

E anode = 0.134 V vs SHE measns its value is always + 0.134.

Even when this electrode is used as anode or cathode with respect to any electrodes always its reduction potential value is +0.134. Soo yoou have use +0.134 value when compared Hydrogen half cell.

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