(50%) Problem 2: A block of mass m = 190 kg rests against a spring with a spring
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(50%) Problem 2: A block of mass m = 190 kg rests against a spring with a spring constant of k= 640 Nm on an inclined plane which makes an angle of degrees with the horizontal. Assume the spring has been compressed a distance d from its neutral position. Randomized Variables m= 190 kg k = 640 N/m ©theexpertta.com 25% Part (a) Set your coordinates to have the x-axis along the surface of the plane, with up the plane as positive, and the y-axis normal to the 25% Part (b) Assuming the coefficient of static friction is 4, write an expression for the sum of the forces in the x-direction just before the 2596 Part (c) Assuming the plane is frictionless, what is the minimum angle in degrees the incline plan can make before the block will move plane, with out of the plane as positive. Write an expression for the normal force, Fv, in the y-direction. block begins to slide if the spring is compressed by 0.1 m? Grade Summar Deductions Potential 100% tan acos atan acotan)sinh Submissions Attempts remaining:3 (400 per attempt) detailed view Sin cos cotan) asin0) coshO tan cotanhO 0 END O Degrees Radians BACKSPACE DEL CLEAR Submit Hint I give up! Hints. 4% deduction per hint. Hints remaining: 4 Feedback: 5% deduction per feedback.Explanation / Answer
(C) If the surface is frictionless than the forces along the surface
MgSin(theta) - KX = 0
Sin(theta) = KX/Mg = 640*0.1 / (190*9.81)
Therefore theta = 1.9677 degree
(d) if the angle is 45 then use above equation and calculate for X
MgSin(theta) = KX
X = 2.05 m
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