A parallel-plate capacitor has an area of 4.70 cm^2 and the plates are separated

Question

A parallel-plate capacitor has an area of 4.70 cm^2 and the plates are separated by 1.00 mm. The capacitor stores a charge of 382.0 pC. What is the potential difference across the plates of the capacitor? The permittivity of a vacuum is 8.8542 Times 10^-12 C^2/N m^2. Answer in units of V. What is the magnitude of the uniform electric field in the region that is located between the plates? Answer in units of V/m. A parallel-plate capacitor has a plate area of 185 cm^2 and a plate separation of 0.0440 mm. Determine the capacitance. The permittivity of a vacuum is 8.85419 Times 10^-12 C^2/N m^2. Answer in units of F. Determine the potential difference when the charge on the capacitor is 450.0 pC. Answer in units of V.

Explanation / Answer

you have asked 2 different questions.As per chegg guidelines i can only answer one.Please raise differenet question for another one.

given are

A=4.70cm^2=4.70*10^-4m^2

d=1mm=1*10^-3 m

Q=382pC=382*10^-12 C

using formula

c=eoA/d

=8.854*10^-12*4.70*10^-4/10^-3

=41.6*10^-13

C=4.16PF

Q=CV

V=Q/c

=382*10^-12/4.16*10^-12

V=91.8V---answer

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