A parallel-plate air capacitor has a capacitance of830 pF. The charge on each pl

Question

A parallel-plate air capacitor has a capacitance of830 pF. The charge on each plate is1.80 µC. (c) How much work is required to quadruple the separation?
3 J
A parallel-plate air capacitor has a capacitance of830 pF. The charge on each plate is1.80 µC. (c) How much work is required to quadruple the separation?
3 J

Explanation / Answer

capacitance of the capacitor is: C=0*A/d => potential energy=E=1/2*Q2/C if the distance is quadrupled , the C'=C/4 => E'=4E the work required to do this is equal to the change in differencepotential energy of the capacitor: E'-E=3/2*Q2/C = 5.86*10-3J

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