A parallel-plate capacitor has an area A = 2.00 10-4 m2 and a plate separation d

Question

A parallel-plate capacitor has an area A = 2.00 10-4 m2 and a plate separation d = 1.00 10-3 m. (a) Find its capacitance. F (b) How much charge is on the positive plate if the capacitor is connected to a 3.00 V battery? C (c) Calculate the charge density on the positive plate, assuming the density is uniform. C/m2 (d) Calculate the magnitude of the electric field between the plates. V/m

Part 2

Two plates, each of area 2.70 10-4 m2, are used to construct a parallel-plate capacitor with capacitance 1.30 pF. (a) Find the necessary separation distance. d = m (b) If the positive plate is to hold a charge of 5.10 10-12 C, find the charge density. = C/m2 (c) Find the electric field between the plates. E = N/C (d) What voltage battery should be attached to the plate to obtain the preceding results? V = V

Explanation / Answer

a) capacitance, C = e0 A / d

C = (8.854 x 10^-12 x 2 x 10^-4) / (1 x 10^-3)

C = 1.77 x 10^-12 F

b) Q = C V = 1.77 x 10^-12 x 3 =5.31 x 10^-12 C

c) Charge density = Q/A = 2.655 x 10^-8 C/m^2

d) E = V/d = 3 / (1 x 10^-3) = 3000 V/m

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