Two 3.00 cm × 3.00 cm plates that form a parallel-plate capacitor are charged to

Question

Two 3.00 cm × 3.00 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC . Part A, What is the electric field strength inside the capacitor if the spacing between the plates is 1.00 mm ? Part B, What is potential difference across the capacitor if the spacing between the plates is 1.00 mm ? Part C, What is the electric field strength inside the capacitor if the spacing between the plates is 2.00 mm ? Part D, What is the potential difference across the capacitor if the spacing between the plates is 2.00 mm ?

Explanation / Answer

PartA) E = Q/€A = 8.9×10^4 N/C

B) V = Ed where d is spacing between the plates hence V = 88.9V

C). Electric field strenght will remain same, it is independent of the spacing.

D) V will change to 2V as in part B as spacing is doubled.

Hence answer will be 177.78V

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