Two 15.0 kg ice sleds are placed a short distance apart, one directly behind the

Question

Two 15.0 kg ice sleds are placed a short distance apart, one directly behind the other, as shown in the figure. A 4.32 kg cat, initially standing on sled 1, jumps across to sled 2 and then jumps back to sled 1. Both jumps are made at a horizontal speed of 2.37 m/s relative to the ice. What is the final speed of sled 2? (Assume the ice is frictionless.)

What is the final speed of sled 1?

I was able to get the final speed of sled 2 (Correct, computer gets: 1.37 m/s ) but I can't seem to get sled 1.

Explanation / Answer

after the first jump ,

speed of sled 1 is u1

as there is no external force acting on the sled- cat system

change in momentum of system is zero

u1 * 15 + 2.37 * 4.32 = 0

u1 = -0.68 m/s

for the sled 2

2.37 * 4.32 = (4.32 + 15)* u2

u2 = 0.53 m/s

after the second jump

- 2.37 * 4.32 + 15 * v2 = 0.53 * 19.32

v2 = 1.37 m/s

the final speed of sled 2 is 1.37 m/s

----for the sled 1

v1 *(4.32 + 15) = -2.37 * 4.32 - 0.68 * 15

v1 = - 1.07 m/s

the final speed of sled 1 is 1.07 m/s

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