Two 10-cm-diameter charged rings face each other, 19 cm apart. The left ring is
ID: 1531424 • Letter: T
Question
Two 10-cm-diameter charged rings face each other, 19 cm apart. The left ring is charged to -15 nC and the right ring is charged to +15 nC .
Part A: What is the magnitude of the electric field E at the midpoint between the two rings?
Part B: What is the direction of the electric field E at the midpoint between the two rings?
To the right ring.
Parallel to the plane of the rings
To the left ring
Part C: What is the magnitude of the force F on a -1.0 nC charge placed at the midpoint?
Part D: What is the direction of the force F on a -1.0 nC charge placed at the midpoint?
To the right ring
To the left ring
Parallel to the plane of the rings
Explanation / Answer
a )
given
d = 19 cm = 0.19 m
Q = 15 n C
D = 10 cm
R = D / 2 = 5 cm = 0.05 cm
the net elecgric field is
Enet = K Q d / ( (d/2)2 + R2 )3/2
Enet = 9 X 109 X 15 X 10-9 X 0.19 / ( 0.19/2 )2 + 0.052 )3/2
Enet = 20731.27 N/C
b )
the Enet is in directed towards the center of the negative charged ring or positive X - direction
c )
F = q Enet
F = - 1 X 10-9 X 20731.27
F = - 20731.27 X 10-9 N
d )
here in this case
the Enet is
the charge at the midpoint is negative the electric force on this particle directs to center of positive charge ring.
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