Please help with 4 + 5. I was able to get 1-3. Two parallel plates, each having

Question

Please help with 4 + 5. I was able to get 1-3.

Two parallel plates, each having area A = 2870cm2 are connected to the terminals of a battery of voltage Vb = 6 V as shown. The plates are separated by a distance d = 0.48cm. You may assume (contrary to the drawing) that the separation between the plates is small compared to a linear dimension of the plate.

1) What is C, the capacitance of this parallel plate capacitor? 5.28674852424928 × 10-4 uF

2) What is Q, the charge stored on the top plate of the this capacitor?. 0.00317204911454957 uC

3) A dielectric having dielectric constant = 3.1 is now inserted in between the plates of the capacitor as shown. The dielectric has area A = 2870 cm2 and thickness equal to half of the separation (= 0.24 cm) . What is the charge on the top plate of this capacitor? 0.00479675719761155 uC

4) What is U, the energy stored in this capacitor?

5)

The battery is now disconnected from the capacitor and then the dielectric is withdrawn. What is V, the voltage across the capacitor?

Explanation / Answer

4) Energy stored = 1/2 QV, I am entering the value of Q calculated by you in third part

=0.5*0.00479675719761155 uC *6V   

=0.0144 *10-6 Joules = 1.44 * 10-8 J

5)Since battery is removed, charge Q is fixed now (calculated in part 3), and we have the capacitance after removing the dialectric (calculated in part 1)

V=Q/C

=0.0048/(5.2867 *10-4) Volt

=9.08 volt

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