Please help to solve the question using formulas without using r, thank you! 8.
ID: 3044668 • Letter: P
Question
Please help to solve the question using formulas without using r, thank you!
8. (20pts) Consider the following questions: give the distribution name, carefully define the random variables you use and find the final answer. (a) (4pts) A professor has made 20 exams of which 8 are hard, 7 are reasonable, and 5 are easy. The exams are mixed up and the professor selects 4 of them at random to give to four sections of the course she is teaching. What is the probability that no sections receive a hard test? (b) (4pts) Suppose a representative at a credit card customer service center receives a phone call every 5 minutes on average. Find the probability that she receives 3 phone calls in 20 minutes. (c) (4pts) Products produced by a machine has a 3% defective rate. what is the probability that the first defective occurs in the fifth item inspected. (d) (4pts) In a class of 100 students, 25 have hardcover and 75 students have paperback textbooks. If you randomly choose 10 students in this class, find the probability that 2 of them have hardcover texts. (e) (4pts) Emily hits 60% of her free throws in basketball games. She had 7 free throws in last week's game. What is the probability that she made at least 5 hits?Explanation / Answer
a)Binomial Distribution
Random variable x is the number of hard tests selected
4 non hard test can be selected from 12 tests, this can be done in 12C4 ways
Required probability = 12C4/20C4 = 0.1022
b) Poisson's Distribution
Random variable x is the number of phone calls received
lambda = 1/5 * 20 = 4
P(X = 3) = e^(-4)*4^3/3! = 0.1954
c) Negative Binomial Distribution
Random variable x is the first occurrance of success
P(X = 5) = (1-0.03)^4 * (0.03) = 0.0266
d) Binomial Distribution
Random variable x is the number of students with hardcover text
p = 25/100 = 0.25
P(X = 2) = 10C2 * 0.25^2 * 0.75^8 = 0.2816
e) Binomial Distribution
Random variable x is the number of hits
p = 0.6
P(X >= 5) = 7C5 * 0.6^5 * 0.4^2 + 7C6 * 0.6^6 * 0.4^1 + 7C7 * 0.6^7 * 0.4^0 = 0.4199
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