A 0.50- F and a 1.4- F capacitor ( C 1 and C 2, respectively) are connected in s

Question

A 0.50-F and a 1.4-F capacitor (C1 and C2, respectively) are connected in series to a 23-V battery.

Part A

Calculate the potential difference across each capacitor.

Express your answers using two significant figures separated by a comma.

Part B

Calculate the charge on each capasitor.

Express your answers using two significant figures separated by a comma.

Part C

Calculate the potential difference across each capacitor assuming the two capacitors are in parallel.

Express your answers using two significant figures separated by a comma.

Part D

Calculate the charge on each capasitor assuming the two capacitors are in parallel.

Express your answers using two significant figures separated by a comma.

Explanation / Answer

C1 = 0.50 u F

C2 = 1.4 uF

V = 23 Volts

a)

Since C1 and C2 are in series , their series combination is given as

C = C1 C2 / (C1 + C2) = 0.5 x 1.4 / (0.5 + 1.4) = 0.368 uF

Q = net charge coming from battery = CV = 23 x 0.368 = 8.46 uC

V1 = potential difference across C1 = Q/C1 = 8.46 / 0.5 = 16.92 volts

V2 = potential difference across C2 = Q/C2 = 8.46 / 1.4 = 6.04 volts

B)

Charge on each = Q = 8.46 uC

c)

Since C1 and C2 are in parallel ,, The potential difference across C1 and C2 will be same and equal to the battery Voltage 23 volts

d)

Q1 = charge stored by C1 = C1V = 0.5 x 23 = 11.5 uC

Q2 = charge stored by C2 = C2 V = 1.4 x 23 = 32.2 uC

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