A 0.50- F and a 1.4- F capacitor ( C 1 and C 2, respectively) are connected in s

ID: 1614660 • Letter: A

Question

A 0.50-F and a 1.4-F capacitor (C1 and C2, respectively) are connected in series to a 6.0-Vbattery.

Part A

Calculate the potential difference across each capacitor.

Express your answers using two significant figures separated by a comma.

Part B

Calculate the charge on each capasitor.

Express your answers using two significant figures separated by a comma.

Part C

Calculate the potential difference across each capacitor assuming the two capacitors are in parallel.

Express your answers using two significant figures separated by a comma.

Part D

Calculate the charge on each capasitor assuming the two capacitors are in parallel.

Express your answers using two significant figures separated by a comma.

c1=0.5 uF ,c2= 1.4 uF

(a) Cs=c1 c2/(c1+c2)

Cs=0.5 *1.4/(0.5+1.4)

Cs=0.368 uF

Q= Cs V

Q= 6(0.386)

Q=2.21 uC.

V1= Q/c1

V1=2.21/0.5

V1=4.4 volts

V2= Q/c2

V2=2.21/1.4

V2=1.6 volts.

(b) charge in both capacitors in series is same =Q=2.2 uC.

(d) Q1= C1 v= 0.5(6)

Q1= 3 uC.

Q2= C2 V= 1.4(6)

Q2=8.4 uC.

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