(&c;/p5o) A 0.30 kg mass sllding on a horizontal frictionless surface is attache

Question

(&c;/p5o) A 0.30 kg mass sllding on a horizontal frictionless surface is attached to ane end of a horizontal spring (wlth k - 5/5 N/m) whase other end is fixed. The mass has a kinetic energy of 1.0J as it passes through its cquilibriurn position (the point at which the spring forco is zo At what rate is the spring doing work on the mass as the mass passes through its equilibrium position? Submit Miswer Tries 0j8 At what rate Is the spring dolng work on the mass when the spring Is compressed 0.122 m and the mass is moving away from the equilibrlum position Submit Answer Tries 0/8

Explanation / Answer

rate of work done = P = F.v

when at equilibrium, F = 0

so rate of work done = 0 ......Ans

when x = 0.122 m

F = k x = (575)(0.122) = 70.15 N  

PE + KE = TE

( (575)(0.122^2)/2 ) + (0.30 v^2 / 2) = 17

v = 9.21 m/s

Rate of work done = - 70.15 x 9.21

= 646 J/s OR watt

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