Two 5.0 mm × 5.0 mm electrodes are held 0.10 mm apart and are attached to 9.0 V
ID: 1584284 • Letter: T
Question
Two 5.0 mm × 5.0 mm electrodes are held 0.10 mm apart and are attached to 9.0 V battery. Without disconnecting the battery, a 0.10-mm-thicksheet of Mylar is inserted between the electrodes.
A)What is the capacitor's potential difference before the Mylar is inserted?
B)What is the capacitor's electric field before the Mylar is inserted?
E=
C)What is the capacitor's charge before the Mylar is inserted?
Q=
D)What is the capacitor's potential difference after the Mylar is inserted? deltaV=
E)What is the capacitor's electric field after the Mylar is inserted? E=
F)What is the capacitor's charge after the Mylar is inserted? Q=
Two 5.0 mm × 5.0 mm electrodes are held 0.10 mm apart and are attached to 9.0 V battery. Without disconnecting the battery, a 0.10-mm-thicksheet of Mylar is inserted between the electrodes.
A)What is the capacitor's potential difference before the Mylar is inserted?
V =B)What is the capacitor's electric field before the Mylar is inserted?
E=
C)What is the capacitor's charge before the Mylar is inserted?
Q=
D)What is the capacitor's potential difference after the Mylar is inserted? deltaV=
E)What is the capacitor's electric field after the Mylar is inserted? E=
F)What is the capacitor's charge after the Mylar is inserted? Q=
Explanation / Answer
we know, dielctric constant of mylar, k = 3.1
A) delta_V = 9.0 V
B) E = delta_V/d
= 9.0/(0.1*10^-3)
= 9.0*10^4 N/c
C) C = A*epsilon/d
= 5^2*10^-6*8.854*10^-12/(0.1*10^-3)
= 2.21*10^-12 F
so, Q = C*delta_V
= 2.21*10^-12*9
= 1.99*10^-11 C
D) delta_V' = 9.0 V
E) E' = 9.0*10^4 N/C
F) Q' = k*Q
= 3.1*1.99*10^-11
= 6.17*10^-11 C
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.