Two 2.20{\ m{ cm}} \\times 2.20{\ m{ cm}} plates that form a parallel-plate capa

Question

Two 2.20{ m{ cm}} imes 2.20{ m{ cm}} plates that form a parallel-plate capacitor are charged to pm 0.708{ m{ nC}} a)What is the electric field strength inside the capacitor if the spacing between the plates is 1.50{ m mm} ? b)What is potential difference across the capacitor if the spacing between the plates is 1.50{ m mm} ? c)What is the electric field strength inside the capacitor if the spacing between the plates is 3.00{ m mm} ? d)What is the potential difference across the capacitor if the spacing between the plates is 3.00{ m mm} ?

Explanation / Answer

q= 0.708e-9

A = 0.022*0.022

epsi = 8.85e-12

a) E = Q/(a*epsi)

E = 165289 N/C

b) d = 1.5e-3

C = epsi*A/d

V = Q/C

V = 247.9 V

c) E = Q/(a*epsi)

E = 165289 N/C

d) d = 3e-3

C = epsi*A/d

V = Q/C

v = 495.9 V

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