2) A 0.060 kg golf ball is af rest and has a velocity of 100.m/s immediately aft

Question

2) A 0.060 kg golf ball is af rest and has a velocity of 100.m/s immediately after being hit. I golf club and ball were in contact for 0.800 ms, what is the average force exerted on the ball (060) (oocooo N , 100 x10-3 3) A 1.30 kg mass moving at 17.6 m/s collides with a stationary mass of 1.25 kg. If the two masses stick together, what is their combined velocity immediately after the collision? 4) A 1250 kg howitzer fires a 11.1 kg mass at4 recoil velocity of the howitzer? Assume that frictional forces are negligible. 5) A 0.140 kg baseball is thrown with an initial velocity of 26.2 m/s. It is struck with an aver

Explanation / Answer

2)

We know that, Force is

F=dp/dt

Where dp is the change in the magnitude and dt is the time taken.

So, force will be

F=0.06*100/0.8*10-3

F=7500N

3)

We know that momentum will remain conserve as their is no external force on the system

Let the final velocity be V

So conserving the momentum .

1.3*17.6=(1.3+1.25)V

V=8.9725m/s

4)

It is similar to previous question, again momentum will be conserved so

(1250-11.1)V=11.1*40

V=0.358m/s

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