HIGH PRESSURE NORMAL PRESSURE LOW PRESSURE 2.0 10 1.5 DISTANCE (ft) 0.5 FIGURE 3
ID: 1583142 • Letter: H
Question
HIGH PRESSURE NORMAL PRESSURE LOW PRESSURE 2.0 10 1.5 DISTANCE (ft) 0.5 FIGURE 3-15 Pressure versus position in the air tube shown. The tube is 2 feet long b) 1. A tube of air has the pressure graph shown in Figure 3-15, the tube must have: a) both ends open b) both ends closed c) left end open, right end closed d) left end closed, right end open e) I don't know 2. Which standing wave is shown in Figure 3-15? a) first harmonic b) first overtone c) second overtone d) third overtone e) none of the above 3. What is the wavelength of this standing wave in Figure 3-15? a) 1 foot b) 2 feet c) 3 feet d) 4 feet e) 8 feet 4. There is a compression in the wave of Figure 3-15 at a)x=0feet. b)x=!foot. c)x?feet. d) the position of the node. e) no place in the tube. 5. Which of the graphs of molecular displacement versus horizontal distance in Figure 3-16 corresponds to the pressure graph in Figure 3-15? 6. When one blows across the opening of a bottle a tone is heard a) only if the bottle contains water so water waves can occur. b) because one of the natural frequencies of the air column in the bottle is excited. c) because the glass in the bottle carries sound waves. d) because air is forced into the bottle and can't get out.Explanation / Answer
At the closed end - antinode of pressure forms
At the open end - mode of pressure forms in case of standing wave..
At x= 0 pressure is maximum and at x=2ft pressure is minimum.. at both places (x=0 and x=2ft) antinode is formed so both ends are closed end.
1. answer is (b) both ends are closed...
2. Answer is (a) It is first harmonic or fundamental mode of vibration..
3. Answer is (d) In the figure shown distance is half of wavelength so wavelength is 4ft
4. Answer is (c) pressure is minimum at x=2ft so the compression..
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