A 54100 kg train car is moving at a speed of 0.72 m/s along a horizontal track.

Question

A 54100 kg train car is moving at a speed of 0.72 m/s along a horizontal track. It is brought to a stop with a spring bumper that has a stiffness of 83600 N/m EXAMPLE NOTES IMAGES DISCUSS UNITS STATS HELP Part Description Answer Chk History How far did the spring compress to bring the train car to a stop? (include units with answer) 25 pts, 100% # tries: 0 Show Details Format Check 296 try penalty Hints: 1,0 What is the force in the spring at the maximum compression? (include units with answer) 25 pts. 100% B. # tries: 0 show Details Format Check 290 try penalty in

Explanation / Answer

A) using law of conservation of energy

Kinetic energy of the train = PE of the spring

0.5*m*v^2 = 0.5*k*x^2

0.5*54100*0.72^2 = 0.5*83600*x^2

x = 0.58 m

B) F = k*x = 83600*0.58 = 48488 N

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