A section of a long wire carrying 3.84 A of current passes through a uniform mag

Question

A section of a long wire carrying 3.84 A of current passes through a uniform magnetic field of strength B=1.30 T (see figure). The magnetic field is contained within a square region of side length A=0.845 m, and the middle section of wire is of length L=0.337 m. Find the magnitude of the force in Newtons that the magnetic field exerts on the wire.

Question 7 (1 point) dl A section of a long wire carrying 3.84 A of current passes through a uniform magnetic field of strength B-1.30 T (see figure). The magnetic field is contained within a square region of side length A-0.845 m, and the middle section of wire is of length L-0.337 m. Find the magnitude of the force in Newtons that the magnetic field exerts on the wire.

Explanation / Answer

Magnetic force on current wire,

F = IL X B (cross product)

on L length section,

F1 = (3.84 x 0.337)(1.30) = 1.6823 N to the right

section other than L,

F2 = (3.84 x 0.845 x 1.30) = 4.218 N toward botton of page.

F1 and F2 are perpendicular,

so F = sqrt[ F1^2 + F2^2] = 4.54 N .....Ans

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