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A freight train has two engines, each with a mass of 50,000 kg, pulling 15 freig

ID: 1579157 • Letter: A

Question

A freight train has two engines, each with a mass of 50,000 kg, pulling 15 freight cars, each having a mass of 40,000 kg. The first engine exerts a force of 80,000 N backward on the tracks, and the second engine exerts a force of 90,000 N hackward on the tracks (a) Calculate the acceleration of the train if the coefficient of rolling friction is02(b) what is t e ince in the coupling between the first and second engine? (c) What is the force between the ninth and the tenth freight cars? What formula would you use? F total net force F80,000 N rmass Crav i Which one is the Cerect formls

Explanation / Answer

(A) N = M g = (2 x 50000 + 15 x 40000)g

N = 700000 g

f = u N = 14 000 g


applying Fnet = m a

80000 + 900000 - (14000 x 9.8) = 700000 a

a = 0.047 m/s^2 .....ans

(B) for first engine,

80000 - (0.02 x 50000 x 9.8)- T = (50000)(0.047)

T = 67.86 x 10^3 N  


(C) on tenth car,


T - (0.02 x 40000 x 9.8) = 40000 x 0.047

T = 9.72 x 10^3 N  

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