An MRI technician moves his hand from a region of very low magnetic field streng

Question

An MRI technician moves his hand from a region of very low magnetic field strength into an MRI scanner's 1.80 T field with his fingers pointing in the direction of the field. Find the average emf induced in his wedding ring, given its diameter is 1.90 cm and assuming it takes 0.230 s to move it into the field. 2.22 mV You are Your r eipt no. is 163-9303 Previoustnes s dissipated by the ring assuming that the resistance of the ring is 1.40 m2 (Discuss whether this current would significantly change the temperature of the ring.) Answer Tries 0/20

Explanation / Answer

Here ,

for the induced emf

induced emf = change in flux/time taken

induced emf = 1.8 * pi * (0.019/2)^2/(0.230)

induced emf = 0.00222 V = 2.22 mV

Now , for the energy

energy = V^2/R * t

energy = 0.0022^2/0.0014 * 0.23

energy = 7.95 *10^-4 J

energy = 0.795 mJ

the energy dissipated is 0.795 mJ

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