An LC circuit is shown in the gure below. The 28 pF capacitor is initially charg

Question

An LC circuit is shown in the gure below.
The 28 pF capacitor is initially charged by the
6 V battery when S is at position a. Then S
is thrown to position b so that the capacitor
is shorted across the 16 mH inductor.

A.
What is the maximum value for the oscillating current assuming no resistance in the
circuit?
Answer in units of A

B.
What is the natural angular frequency of the
circuit?
Answer in units of rad/s

C.
What is the maximum energy stored in the
magnetic eld of the inductor?
Answer in units of J

Explanation / Answer

A. q=C*V q= (28E-11)*(6) = 1.68E-9 C I = w*Qo*sin(wt) where w is the angular frequency. I will be maximized when sin(wt) goes to 1. Therefore, Imax = w * Qo, and w = 1/sqrt(LC). Therefore, Imax = 0.000794 A. B. w = 1/sqrt(LC) = 472455.59 rad/s C. Ul = 1/2*L*I^2. = 1/2*(0.016)*(0.000794)^2 = 5.04 E -9 J

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