The image shows a rod sliding without friction at a constant speed of 5.0 m/s ac
ID: 1569867 • Letter: T
Question
The image shows a rod sliding without friction at a constant speed of 5.0 m/s across two rails separated by 0.45 m, in the presence of a magnetic field of 0.75 T, directed as shown. The resistor has a resistance of 12.0 omega. (a) Find the magnitude and direction (clockwise or counterclockwise) of the induced current in the loop. (b) Determine magnitude and direction of the force required to pull the rod at the speed indicated in part (a). In both parts, provide an explanation for your answers about directions using the right-hand-rule.Explanation / Answer
(a) induced emf = B L v
e = 0.75 x 0.45 x 5 = 1.6875 volt
I = e / R = 0.14 A
direction = clockwise
(b) F = IL x B = 0.14 x 0.45 x 0.75
F = 47.5 x 10^-3 N
to the right
for a: field is out of page and flux is increasing.
so induced current will oppose the change in flux.
hence current will be such that direction of magnetic field due to induced current will be into the page.
that means current is clockwise.
b: current is downward -> IL = downward
B -> out of page
F = IL X B = to left
hence magnetic force will be to the left.
to keep Fnet = 0 ; applied force will be of same magnitude but in opposite direction,
that is to the right.
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