The image below shows a 2D cross-section of the equipotential surface for three
ID: 1286282 • Letter: T
Question
The image below shows a 2D cross-section of the equipotential surface for three point charges. The bottom left one is positively charged with charge Q. Use this diagram to answer the following questions:
a) What can we say about the charge in the middle of the diagram?
negative and equal in magnitude to Q
positive and smaller in magnitude than Q
negative and larger in magnitude than Q
negative and smaller in magnitude than Q
positive and larger in magnitude than Q
positive and equal in magnitude to Q
b) What can we say about the charge in the upper right of the diagram?
negative and larger in magnitude than Q
negative and smaller in magnitude than Q
negative and equal in magnitude to Q
positive and smaller in magnitude than Q
positive and equal in magnitude to Q
positive and larger in magnitude than Q
c) How does the field strength compare at these points? (Rank from greatest to least E).
D > B > A > C
D > C > A > B
C = A > D > B
B > A > C > B
B > D > C > A
B > D > C = A
C > A > B > D
NW
N
NE
S
E
SW
No field here
W
SE
No field here
NW
E
SE
NE
N
W
SW
S
NW
S
E
SW
NE
SE
W
No field here
N
g) At what point, if any, is V = 0?
C
D
There is one, but not marked with a letter
A
B
There is none anywhere on the plot shown
h) At what point, if any, is there an equilibrium?
B
A
There is none anywhere on the plot shown
There is one, but not marked with a letter
C
D
i) At what point of those marked is the potential the highest?
C
B
A
D
Can't be determined
j) As you move from A to B in a nearly straight line (just missing the point charge), you move:
uphill and then downhill in V, ending up higher than you started.
uphill and then downhill in V, ending up at the same V.
downhill and then uphill in V, ending up lower than you started.
at constant V the entire way.
downhill and then uphill in V, ending up higher than you started.
downhill in V the entire way.
downhill and then uphill in V, ending up at the same V.
uphill in V the entire way.
uphill and then downhill in V, ending up lower than you started.
BExplanation / Answer
negative and smaller in magnitude than Q
negative and smaller in magnitude than Q
C = A > D > B
NE
W
S
A
B
C
downhill and then uphill in V, ending up lower than you started
WE ARE!
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