A system undergoes a two-step process. In the first step, the internal energy of

Question

A system undergoes a two-step process. In the first step, the internal energy of the system increases by 215 J when 150 J of work is done on the system. In the second step, the internal energy of the system increases by 111 J when 176 J of work is done on the system. For the overall process, find the heat. J What type of process is the overall process? isobaric isothermal isochoric adiabatic none of the above Explain your choice. The heat is zero. The internal energy increases. Work is done on the system.

Explanation / Answer

a)Heat = Change in internal energy - work done on system

= 215-150+111-176

= 0J

b)adiabatic

c)The heat is zero.

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