Drops of rain fall perpendicular to the root of a parked car during a rainstorm.

Question

Drops of rain fall perpendicular to the root of a parked car during a rainstorm. The drops strike the roof with a speed of 16 m/s, and the mass of rain per second striking the roof is 0.056 kg/s. (a) Assuming the drops come to rest after striking the roof, find the average force exerted by the rain on the roof. magnitude N direction (b) If same mass as the raindrops fall on the roof at the same rate and with the same speed, how would the average force on the roof compare to that found in part (a)? (Assume the hailstones off the roof.) The magnitude would be double that in part (a). The magnitude would be the same as in part (a). The magnitude would be half that in part (a). The magnitude would be one fourth times in part (a).

Explanation / Answer

Impulse = Force x time

Impulse = mass x (final velocity - initial velocity)

force f = m*(v-u)/t

f = 0.056*16

f = 0.896 N

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