At a distance R from a current carrying wire, what is the direction of the magne
ID: 1564914 • Letter: A
Question
At a distance R from a current carrying wire, what is the direction of the magnetic field relative to the wire? a) radially toward the wire b) parallel to the wire c) in the direction that is perpendicular to both the wire and to the radial direction d) in the direction opposite to that of the current e) radially away from the wire The normal to a certain 1.0 m^2 area makes an angle of 45 degree with a uniform magnetic field. The magnetic flux through this area is the same as the flux through a second area that is perpendicular to the field if the second area is: A) 1.0 m^2 B) 0.77 m^2 C) 0.71 m^2 D) 0.45 m^2 E) 0.82 m^2 The figure below describe the image (I) of an object formed by a convex lens, the image in A and B are: a) Both real b) both virtual c) real in B, but virtual in A d) real in A, but virtual in B e) more information is needed A light beam is incident on heavy flint glass (n_2 = 1.33) from air (n_1 = 1) at an angle of theta_1 = 50 degree, as shown figure below. The refractive angle theta_2 is a) 40.0 degree b) 50.0 degree c) 35.2 degree d) 28.2 degreeExplanation / Answer
Question 11: The magnetic field direction is provided by the right hand rule, considering that the thumb point to the direction of the current flowing. In this case, the answer will be C.
Question 12: We can consider the projection of the tilted area with the perpendicular area. In that case, the required area will be 1 m2 cos(35 degree) = 0.82 m2. The answer is E.
Question 13: Looking at the place where the image is formed (one behind lens and one after lens), the image is real in A and virtual in B. The answer is B.
Question 14: From Snell's Law, Sin(theta1)/Sin(theta2) = n2. Considering this, theta2 = Sin-1[Sin[50]/1.62] = 28.2 degree. The answer is D.
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